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Maths at work 1 – A fencing job
Answers
- Length of each side of the paddock = 100m
Length of fence = 4 x 100 = 400m
- The gate should be positioned in a corner to limit the number
of strainer posts to five and to allow the easiest movement of stock in and
out of the paddock.
- Five strainer posts will be needed, one at each corner and one
on the other side of the gate.
- Eight diagonal stays will be required.
- A total of 95 posts will be needed. 24 fence posts are needed
per side, which means that 96 posts, less one post in the position of the gate
strainer.
- Length of side of paddock = 100m
For 3 sides length of each wire = 102m
Length of wire needed for 3 sides = 3 x 5 wires x 102m = 1530m of wire
For 4th side (with gateway) length of each wire = 98m
Length of wire needed = 5 x 98m = 490m of wire
Total length of wire = 1530 + 490 = 2020m
- No. rolls of wire = 2020 / 500 = 4.04
Note – Most properties will have unfinished rolls of wire from previous jobs to use where short lengths are needed.
- Cost of materials
| MATERIAL | COST PER UNIT | NO. OF UNITS | TOTAL COST |
|---|---|---|---|
| Strainer post | $20.00 | 5 | 100.00 |
| Stay | $12.00 | 8 | 96.00 |
| Fence post | $8.00 | 95 | 760.00 |
| Roll of high tensile barbwire | $70.00 | 4 | 280.00 |
| Gate (3.6m) and fittings | $120.00 | 1 | 120.00 |
TOTAL COST |
$1356.00 | ||
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