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9.3 Motors and generators: 1. Motors and magnetic forces

Problem:

A conductor of length 0.20 m and carrying a current of 2.0 A lies in a magnetic field of strength 1.0 x 10-5 T. The conductor experiences a force of 2.0 x 10-6 N. Calculate the angle between the length of the conductor and the direction of the magnetic field.

Solution:

F = B I l sin theta

Rearrange the equation to get sin theta alone:

sin theta = F / B I l
    = (2.0 x 10-6) / (1.0 x 10-5 x 2.0 x 0.20) = 0.5

therefore, theta = 30°

The conductor lies at an angle of 30° to the direction of the magnetic field.

 

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