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9.3 Motors and generators: 1. Motors and magnetic forces
Problem:
A conductor of length 0.20 m and carrying a current of 2.0 A lies in a magnetic field of strength 1.0 x 10-5 T. The conductor experiences a force of 2.0 x 10-6 N. Calculate the angle between the length of the conductor and the direction of the magnetic field.
Solution:
sin 90°="1
F = B I l sin 
Rearrange the equation to get sin alone:
sin = F / B I l
= (2.0 x 10-6) / (1.0 x
10-5 x 2.0 x 0.20) = 0.5
therefore, = 30°
The conductor lies at an angle of 30° to the direction of the magnetic field.
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