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9.5 Industrial Chemistry: 6. Solvay Process

Syllabus reference (October 2002 version) 

Answers:

  1. Calculate moles
        From the periodic table, molar mass of  Na2CO3 = 2 x 22.99 + 12.01 + 3 x 16.00 = 105.99 g
        no mol in 325 000 tonnes = 325 000 x 1 000 000/105.99 = 3066 327 000 mol

    From the equation:
    1 mol Na2CO3 produced from 1 mol CaCO3
    3 066 327 000 mol Na2CO3 produced from 3 066 327 000 mol CaCO3

    Moles to mass
    1 mol CaCO3 = 40.08 + 12.01 + 3 x 16.00  = 100.09 g
    3 066 327 000 mol CaCO3 = 100.08 x 3 066 327 000 = 306 878 006 200 g = 306 878 tonnes CaCO3

    1. NaCl(aq) + NH3(g) + H2O(l) + CO2(g)  right arrow  NH4Cl(aq) + NaHCO3(aq)
    2. 50% 650 000 = 325 000 tonnes

    Calculate moles
    1 mol NaCl = 22.99 + 35.45 = 58.44 g
    325 000 tonnes = 325.000 x 1 000 000/58.44 = 5 561 259 411 mol NaCl

    From the equation
    1 mol NaCl reacts with 1 mol NH3
    5 561 259 411 mol NaCl reacts with 5 561259 411 mol NH3

    Moles to mass
    Moles to mass equation

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