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9.7 Option – Genetics: The Code Broken? : 3. Inheritance of genes
| Syllabus reference (October 2002 version) | ||
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3. Studies of offspring reflect the inheritance of
genes on different chromosomes and genes on the same
chromosomes
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Students learn to:
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Students: |
[Edit:12Jun09]
Prior learning: Stages 4 and 5 Science, 5.8.2 c) and d)
HSC 9.3.3 and 4
use the terms ‘diploid’ and ‘haploid’ to describe somatic and gametic cells
process information from secondary sources to analyse the outcome of dihybrid crosses when both traits are inherited independently and when they are linked
A web site that could be useful on linkage,
Dr Paul’s Virtual Biology Show,
Johnson County
Community College, Overland Park, Kansas, USA
perform a first-hand investigation to model linkage
describe outcomes of dihybrid crosses involving simple dominance using Mendel’s explanations
a) Pure breeding, double homozygous tall stem with round seed plant is crossed with double homozygous short stem with wrinkled seed:
Parents: TTRR x ttrr
Possible gametes: TR, TR, TR, TR and tr, tr, tr, tr
F1 : genotypes: all TtRr
phenotypes: all tall stem, round seedBreed two F1 individuals together:
F1: TtRr x TtRr
Possible gametes: TR, Tr, tR, tr and TR, Tr, tR, tr
F2:
gametes TR Tr tR tr TR TTRR TTRr TtRR TtRr Tr TTRr TTrr TtRr Ttrr tR TtRR TtRr ttRR ttRr tr TtRr Ttrr ttRr ttrr
Genotypes Number Phenotypes TTRR 1 Tall stem, round seed TTRr 2 Tall stem, round seed TtRR 2 Tall stem, round seed TtRr 4 Tall stem, round seed TTrr 1 Tall stem, wrinkled seed Ttrr 2 Tall stem, wrinkled seed ttRR 1 Short stem, round seed ttRr 2 Short stem, round seed ttrr 1 Short stem, wrinkled seed
The phenotypic ratio of F2 individuals is:
9 tall round : 3 tall wrinkled : 3 short round : 1 short wrinkled
According to Mendel, because chromosomes segregate independently and all genes are inherited independently, there is an equal chance of the four different types of possible gametes being produced to result in this outcome.
b) Parents: TtRr (tall round) x ttrr (short wrinkled)
Possible gametes: TR, Tr, tR, tr trF1:
gametes TR Tr tR tr tr TtRr Ttrr ttRr ttrr 25% TtRr : 25% Ttrr : 25% ttRr : 25% ttrr
predict the difference in inheritance patterns if two genes are linked
EF ef EF EEFF EeFf ef EeFf eeff producing a ratio of 3 EF : 1ef
All of Mendel’s results were for genes that were inherited independently of each other. This led to his law of independent assortment. Sutton and Boveri later explained this when they observed that chromosomes separate independently during meiosis. Mendel’s results would have been different if any of the traits that he studied had been linked.
Some results from crossing linked genes do not show the exact predicted results as some genes undergo recombination. This recombining of certain genes occurs during meiosis when homologous chromosomes have undergone DNA replication and pair up. At this time, crossing over may occur where sections of chromosomes break off at a point and then recombine with the “wrong” piece of chromosome or swap.
A pair of homologous chromosomes contains the following linked genes A, B, C and D:
____AB_____CD_____
_________X_________
AB CD A homologous pair of chromosomes after DNA replication. Crossing over occurs at X
____ab______cd________
________X____________
ab cdIf crossing over did not occur, the four potential chromosomes would be: ABCD, ABCD, abcd and abcd.
If crossing over of the two inner chromatids occurs at X, then the resulting chromosomes would be: ABCD, ABcd, abCD, and abcd. Crossing over only occurs between homologous chromosomes and is only an important factor in linked genes.
____AB_____CD________
______________________
AB cd
____ab_____CD_______
________X___________
ab cd
explain how cross-breeding experiments can identify the relative position of linked genes
Example:
Genes A, B and C are linked. In a cross breeding
experiment, ABC was crossed with abc and the percentages of
recombinations were observed.
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AB x ab
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Results: AB and ab 85%
Ab and aB 15% (recombined through crossing over) |
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BC x bc
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Results: BC and bc 95%
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AC x ac
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Results: AC and ac 90%
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A and B are 15 units apart
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A ________________15 _______________ B |
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B and C are 5 units apart
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B ____5___C |
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A and C are 10 units apart
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A ________10 _________C |
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The resulting map is:
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A __________10__________C______5_____B |
discuss the role of chromosome mapping in identifying relationships between species